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Liono4ka [1.6K]
3 years ago
9

Given the parent function of f(x) = x3, what change will occur when the function is changed to f(x) − 3?

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0

For this case we have that the main function is given by:

f (x) = x ^ 3

We apply the following transformation:

Vertical displacements:

Assume k> 0

To graph y = f (x) - k, move the graph k units down.

For k = 3 we have:

y = f (x) - 3\\y = x ^ 3 - 3

Answer:

when the function is changed to f (x) - 3 the change that will occur is:

Vertical displacement 3 units down.

Serjik [45]3 years ago
3 0
The function line will move down 3 units.
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System of equations <br><br> -8x + 4y = 24<br> -7x + 7y = 28<br><br> X= ___<br> Y=___
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The circumference of the bike tire above is 83.524 inches. What is the radius of the bike tire? (Use 3.14 for .) A. 262.27 in B.
Shtirlitz [24]

Answer:

Option <u>C. 13.3 in</u>.

Step-by-step explanation:

Here's the required formula to find the radius of the bike tire :

\longrightarrow{\pmb{\sf{C_{(Circle)} = 2\pi r}}}

  • C = circumference
  • π = 3.14
  • r = radius

Substituting all the given values in the formula to find the radius of the bike tire :

\begin{gathered} \qquad{\longrightarrow{\sf{C_{(Circle)} = 2\pi r}}} \\  \\ \qquad{\longrightarrow{\sf{83.524 = 2 \times 3.14 \times  r}}}  \\  \\ \qquad{\longrightarrow{\sf{83.524 = 6.28 \times  r}}} \\  \\ \qquad{\longrightarrow{\sf{83.524 = 6.28r}}} \\  \\  \qquad{\longrightarrow{\sf{r =  \frac{83.524}{6.28}}}} \\  \\ \qquad{\longrightarrow{\sf{r  =  13.3 \: in}}} \\  \\ \qquad  \star{\underline{\boxed{\sf{\red{r  = 13.3 \: in}}}}}\end{gathered}

Hence, the radius of bike tire is 13.3 inches.

\rule{300}{2.5}

6 0
2 years ago
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