If I understood the task, then here are the answers: 1/2=2/4 or 0.5=1/2
In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
Answer:
Y= -3/5 - 1
Step-by-step explanation:
if you start on the y intercept an go down once (-1)
then go down three times (-3)
positive 5 so go right 5 times it lands on the point :)
im not a teacher and i took this last year so sorry if my explanation isn't the best
PLEASE PLEASE PLEASE PLEASE (5'1, 5'2, 5'3, 5'4, 5'5, 5'6, 5'7, 5'8, 5'9, 5'9, 5'10, 5'11, 5'12)
Yakvenalex [24]
Answer:5
5 feet 7 inches
Step-by-step explanation:
first add all of the given together and then divide what you get by the number of terms given
(5'2+5'3+5'4+ 5'5+5'6+ 5'7+ 5'8+5'9+5'9,+5'10+5'11+5'12)/12 = 5'7 11/64 inches
then divide 11 by 64 on a calculator and then round the decimal you get to the nearest tenth which gives you the answer 5 feet 7 inches.
