Answer:
12.306
Explanation:
12.3+0.005675=12.305675 just put answer as 12.306
The final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.
SPECIFIC HEAT CAPACITY:
- The amount of heat absorbed or released by a substance can be calculated using the following formula:
- (m × c × ∆T) water = - (m × c × ∆T) metal
According to this question;
METAL:
- m = 30.6g
- c = 0.380 J/g°C
- ∆T = T - 87.4°C
WATER:
- m = 62.3g
- c = 4.184J/g°C
- ∆T = T - 28.3°C
- 62.3 × 4.184 × (T - 28.3) = - {30.6 × 0.380 × (T - 87.4)}
- 260.7T - 7376.8 = - {11.63T - 1016.3}
- 260.7T - 7376.8 = -11.63T + 1016.3
- 260.7T + 11.63T = 1016.3 + 7376.8
- Therefore, the final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.
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On the cumulative Report, it would be much easier to read for the patients if the ranges in parentheses were tabbed over from the actual result instead of printing directly one space after the result.