All categories

4 years ago

I need help on 22 please .~.

Mathematics

1 answer:

Verdich [7]4 years ago

5 0

You have to do 1.5 times 2 and that equals something and that times 1.7

You might be interested in

The manager of a furniture factory finds that it costs $2400 to manufacture 60 chairs in one day and $4800 to produce 260 chairs

tamaranim1 [39]

Answer:

C(x) = 12x + 1680

Slope = 12

Intercept = 1680

Step-by-step explanation:

Given that:

X1 = 60 chairs ; y1 = 2400

X2 = 260 chairs ; y2 = 4800

Obtain the slope ; m

m = y2 - y1 / x2 - x1

m = 4800 - 2400 / 260 - 60

m = 2400 / 200

m = 12

Using the point slope relation:

y - y1 = m(x - x1)

y - 2400 = 12(x - 60)

y - 2400 = 12x - 720

y = 12x - 720 + 2400

y = 12x + 1680

C(x) = 12x + 1680

From the general slope intercept equation :

y = mx + c

m = slope ; c = intercept

Hence,

C(x) = 12x + 1680

Slope = 12

Intercept = 1680

5 0

3 years ago

Find the volume of the Grain silo show below that has a diameter of 20ft and a height of 50ft

Aleks [24]

$Volume=Area_{base}*height\\\\
Volume= \pi radius^2*height\\\\
diameter=2radius\\
radius=10ft\\\\
Area= \pi 10^2*50=5000 \pi ft^3\\\\
Volume\ of\ Grain\ silo\ is\ 5000 \pi ft^3.$

3 0

3 years ago

Find the value of x to the nearest degree.

bazaltina [42]

I believe it’s D sorry if I’m wrong

6 0

3 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05