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3 years ago

Разделите дробь 1 3/7 в отношении 3:17

Mathematics

1 answer:

svetoff [14.1K]3 years ago

6 0

What language is that 0-0

answer: <span>3*17 токо так</span>

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Is it proportional or non proportional

natta225 [31]

Answer:

proportional

Step-by-step explanation:

13/2=6.5

19.5/3=6.5

26/4=6.5

32.5/5=6.5

so if all equal the same they are proportional

6 0

3 years ago

A bakery has 2,160 loaves of whole-wheat bread in July. In all, the bakery SOLD 9000 loaves THIS MONTH. What percent of the loav

Bumek [7]

24% because you would make a ratio like x/100= 2,160/9000. So basically the x is the percentage you need, 100 is just an easy factorable percent, and 2,160 is the wheat bread and 9000 is all the bread. Basically what you do with this ratio is you cross multiply. This means you multiply 2,160 by 100 and divide by 9000 and that’s your percent

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4 years ago

64.3 - 3 x 2 by the power of 3 divided by two

kolbaska11 [484]

If you meant:

64.3-3*(2³)/2

That would be 52.3 :)

8 0

3 years ago

Read 2 more answers

A Bar of steel is 340 cm long Issa cuts two 55cm lengths of the bar He then cuts the rest into as many 40cm lengths as possible

Assoli18 [71]

Answer:

5 bars

Step-by-step explanation:

340-(55+55)

230÷40

5.75

6 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$

c) In this case, t=0.25, so we recalculate the parameter as:

$\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5$

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

$E(x)=\lambda=1.5$

3 0

3 years ago