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3 years ago

How many different rectangles are there that has a perimeter of 100 centimeters

1 answer:

3 0

The factor pairs of 100 are 1 and 100, 2 and 50, 4 and 25, 5 and 20, and 10 and 10. As such, you can only have 5 rectangles with different side lengths assuming all side lengths are integers.

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I need help please i would be grateful

vitfil [10]

N+9

The other factor is n-6

Once multiple together, you will get the same equation again

3 0

3 years ago

Which point represents the x-intercept of this exponential function?

horsena [70]

Answer:

Step-by-step explanation:

the answer is unknown because there is no answer to that question and if there was it would be odd an would not make sence so that is a true of false question

6 0

3 years ago

Read 2 more answers

Opinions please! Get Points! Im doing a research paper in school for English (and part math) and my topic is "Is NASA a Waste of

Irina-Kira [14]

The thing with nasa is that when they use money to build and land things such as space rovers or space shuttles, the money that is used is put back into the economy instead of just floating in space. So the idea that its a waste could easily be debunked by the fact that the money that is used is still in the economy, whether or not you believe the exploration of space is needed could also be a solid point for your paper. Hope that I could help, Good luck with your paper

7 0

3 years ago

Brainlist<br> Please help me

creativ13 [48]

Answer:

Yes she made an error. Explanation is below.

Step-by-step explanation:

Let the sample space for a six sided number cube be S

$n(S) = \{1,2,3,4,5,6\}\\n(S) = 6$

Let the event of a number getting greater than two be B

$n(B) = \{3,4,5,6\}\\n(B) = 4$

To find:

the probability of complement of B that is

p(~B) = ?

Solution"

First we need to solve probability for number getting greater than two

$p(B) = \frac{n(B)}{n(S)}$

Now substituting the values we get

$p(B) = \frac{4}{6}$

$p(B) = \frac{2}{3}$

but we need complement of B so

$p(\textrm{complement of B)} = 1 - p(B)\\p(\~B) = 1 - p(B)\\p(\~B) = 1 - \frac{2}{3}\\ =\frac{1}{3} \\$

P(complement of rolling a number greater than two) = $\frac{1}{3}$

3 0

3 years ago

Please send me answer. tomorrow is my exam.

masha68 [24]

Answer:

The table is attached below and ogive also.

Step-by-step explanation:

Given

The following distribution is given below

First we find the cumulative frequency.

And then we convert it into a less than type ogive.

find the cumulative frequency shown below clearly

And convert it into less than type of cumulative frequency distribution is also done in next table, the daily income is less than daily income upper limit.

In this graph x-axis is daily income and y-axis is number of workers

6 0

3 years ago