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krok68 [10]
3 years ago
13

What's the square root of 48x^6?

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Factor 48 into its prime factors
          <span> 48 = 24 • 3 </span>

To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.

Factors which will be extracted are :
          <span> 16 = 24 </span>

Factors which will remain inside the root are :
           3 = 3 

To complete this part of the simplification we take the squre root of the factors which are to be extracted. We do this by dividing their exponents by 2 :
          <span> 4 = 22 </span>

At the end of this step the partly simplified SQRT looks like this: 
        <span> 4 • sqrt (3x3y4)  </span>

<span>Step  2  :</span>Simplify the Variable part of the SQRT

Rules for simplifing variables which may be raised to a power:

   (1) variables with no exponent stay inside the radical
   (2) variables raised to power 1 or (-1) stay inside the radical
   (3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:
    <span>  (3.1) sqrt(x8)=x4
     (3.2) sqrt(x-6)=x-3

 </span>   (4) variables raised to an odd exponent which is  >2  or  <(-2) , examples:
    <span>  (4.1) sqrt(x5)=x2•sqrt(x)
     (4.2) sqrt(x-7)=x-3•sqrt(x-1)

 </span>Applying these rules to our case we find out that 

     <span> SQRT(x3y4) = xy2 • SQRT(x) </span>

Combine both simplifications

        <span> sqrt (48x3y4) =
        4 xy2 • sqrt(3x) </span>

Simplified Root :     <span> 4 xy2 • sqrt(3x) 
</span>
Hope this helps~!
Happy studying~!
~{Dunsforhands}
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                                  =[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]

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