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ludmilkaskok [199]
3 years ago
15

The question is identify the graph that represents the equation y-2=4(x-5) can someone help me

Mathematics
1 answer:
wolverine [178]3 years ago
4 0
Line
for me convert to slope intercept form
y=mx+b
m=slope
b=y intercept, aka whre the line crosses the y axis

y-2=4(x-5)
y-2=4x-20
y=4x-18
slope=4
yint=-18
positive slope so it goes from bottom left to top right
crosses y axis at -18

first 2 don' cross at -18
3rd, dunno
4th, is going from top left to bottom right, incorrect


answer is 3rd one
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Charlie is thinking about buying a game for his Xbox that cost $60 and requires a subscription to basic Xbox live that cost $10
Nitella [24]

Answer:

by 12 months both prices will be 180.

Step-by-step explanation:

If you take 12 and multiply it by 10 because that is the monthly subscription, you will get 120 + 60 for the game which equals 180. But if you take 12 and multiply it by 15 you will also get 180.

Hope this helps

3 0
3 years ago
Read 2 more answers
According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0
2 years ago
Given the figure below. What is the theorem or postulate that justifies triangle ABD congruent
Zina [86]

Answer:

SAS is the answer in my opinion

7 0
3 years ago
Im confusedd, please help??
spayn [35]

Answer:  three sets of value show 3 consecutive increases and they could be the intensities during fourth, fifth, and six visits:

  • 66%, 69%, 72%;
  • 63%, 65%, 67%, and
  • 67%, 72%, 77%

Explanation:


1) The program recommends a constant intensity for 3 visits, which is what the table shows:

Day        Intensisty

1             63%

2            equal ⇒ 63%

3            equal ⇒ 63%


2) Hence, you have to determine the valid sets that meet the recommendation for the fourth, fifth, and six visits, which are the next three.


2) For the next three visits, the program recommensd increasing intensities.


There are three options that show 3 consecutive increases; they are:

  • 66%, 69%, 72%;
  • 63%, 65%, 67%, and
  • 67%, 72%, 77%

Therefore, those are the choices that apply.

4 0
4 years ago
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