(4,-2)(5,0)
slope(m) = (0 - (-2) / (5 - 4) = 2/1 = 2
there is going to be 2 possible answers...
y - y1 = m(x - x1)
now we sub
using points (4,-2)..... y -(-2) = 2(x - 4) =
y + 2 = 2(x - 4) <==
using points (5,0)....y - 0 = 2(x - 5) <==
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Answer:
Step-by-step explanation:
<u>Area of trapezoid formula:</u>
<u>Substitute the values on the sketch and find the area:</u>
- A = (9 + 13)*10/2 = 110 in²
