Answer:
The rising of shied hero, last hope, and dragon pilot.
Answer:
RAID level 5 can be used to compensate a limited number of available disks.
Explanation:
There are two type of RAID
- Software RAID
- Hardware RAID
Software RAID
deliver services form the host.
Hardware RAID
provides hardware services.
RAID has levels
0, 1, 5, 6, and 10
RAID 0, 1, and 5 work on both HDD and SSD media,
4 and 6 also work on both media.
RAID 0 :Striping
In this level minimum of two disks,RAID 0 split the file strip the data.Multiple hard drive are used to split the data.
RAID 1 : Mirroring
In this level Minimum two disk require and provide data tendency.
RAID 5 :Stripping with parity
Parity is a binary data.RAID system calculate the value which system used to recover the data.
Most RAID system with parity function store parity blocks.
RAID 5 combines the performance of RAID 0 with redundancy of RAID 1.
RAID 5 level should minimize the fault tolerance.
The line code will create array is G = array('f',[2.5, 3, 7.4])
<h3>What is meant by array ?</h3>
As opposed to defining distinct variables for each value, arrays are used to hold numerous values in a single variable. Set the data type (such as int) and the array name, followed by square brackets [, to construct an array.
An array is a collection of elements with the same type that are kept in nearby memory locations and may each be separately referred to using an index to a special identifier. There is no need to declare five distinct variables when declaring an array of five int values (each with its own identifier).
In the C programming language, arrays are a derived data type that may contain primitive data types like int, char, double, float, etc.
To learn more about array refer to :
brainly.com/question/28061186
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Answer:
int x;
indata.open("lottowins");
indata >> x;
cout << x << endl;
indata >> x;
cout << x << endl;
indata >> x;
cout << x << endl;
indata.close();
Answer:
Option d is the correct answer for the above question.
Explanation:
- The first loop of the program has a second loop and then the statement. In this scenario, the second loop executes for the value of the first loop and the statement executes for the value of the second loop.
- The first loop executes 4 times, Then the second loop or inner loop executes n times for the n iteration of the first loop, for example, 1 time for the first iteration of the first loop, 2 times for the second iteration of the first loop and so on.
- Then the inner loop executes (1+2+3+4) iteration which gives the result 10 iterations.
- The sum initial value is 0 and the "sum++", increase the value of the sum by 1.
- So the value of the sum becomes 10 after completing 10 iterations of the inner for loop.
- Hence the 10 will be the output. So the Option d is the correct answer while the other is not.