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crimeas [40]
2 years ago
13

What is the root of 6x-48=0

Mathematics
1 answer:
enot [183]2 years ago
6 0
Undistribute 6
(6)(x-8)=0
set to zero
x-8=0
add 8 to both sides
x=8
the root is at x=8
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How much would it cost to buy a piece of candy for 50 cents plus tax
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Answer:

it depends on which state your in or in your even in the us usually it is either 6% or 4% some times more or less % so im going to do both

50*0.06=53

50*0.04=52

Hope This Helps!!!

5 0
1 year ago
The variable z is inversely proportional to x. When x is 16, z has the value 0.875. What is the value of z when x= 21?
ziro4ka [17]
For z and x to be inversely proportional, there must be some constant k such that

zx=k

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3 years ago
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katrin2010 [14]
Given:
Scale of the map 1 1/4cm : 8 yards
Rectangular Park:  width : 2 1/2 cm ; length : 6 1/4 cm
Circular Pond: pi = 3.14 ; diameter 1 1/4 cm

Convert mixed factions into fractions.
Scale 1 1/4 = (4*1+1)/4 = 5/4
Width: 2 1/2 = (2*2+1)/2 = 5/2
Length: 6 1/4 = (4*6+1)/4 = 25/4
Diameter: 1 1/4 = (4*1+1)/4 = 5/4

width / scale * 8 yds = width in yards
5/2 ÷ 5/4 = 5/2 * 4/5 = 20/10 = 2 * 8 yds = 16 yds
length / scale * 8 yds = length in yards
25/4 ÷ 5/4 = 25/4 * 4/5 = 100/20 = 5 * 8 yds = 40 yds

Area of a rectangular park = l * w = 40 yds * 16 yds = 640 yds² 
 
diameter / scale * 8 yds = diameter in yards
5/4 ÷ 5/4 = 5/4 * 4/5 = 20/20 = 1 * 8 yds = 8 yds.

radius = d/2 = 8/2 = 4
Area of a circular pond = πr² = 3.14 * 4² = 3.14 * 16yds² = 50.24 yds²

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If a school policy maker wanted to learn what expectations must be met to receive funding from H.R.5, what titles would that per
lukranit [14]
I'm definite about a b c
7 0
3 years ago
The drama department was considering two options for the winter production. They used the following equations to represent the p
stellarik [79]

Answer:

Graph D is correct

Step-by-step explanation:

This is complicated because the scales on the x-axis and y-axis are not the same. Graph D has the correct y-intercepts and the correct slopes. The solution is x = 500, where the two lines intersect.

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