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Charra [1.4K]
3 years ago
13

x}^{2} = 0" alt="5 {x}^3 - 20 {x}^{2} = 0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
adell [148]3 years ago
7 0

5x^{2}  \times (x - 4) = 0 \\ x^{2} \times (x - 4) = 0 \\  {x}^{2} = 0 \: x = 0 \\ x - 4 = 0 \: x = 4
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Answer:

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Step-by-step explanation:

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The answer is 20.  The way I do it is divide 12 by 6 then multiply it by 10 (it works as long as the denominator is ten).
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