Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways = 
=126
= 
=
Pv=4,725×((1−(1+0.10÷2)^(−2
×15))÷(0.10÷2))=72,634.83
2.60
so <em>5</em><em> </em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em> </em><em>p</em><em>e</em><em>p</em><em>p</em><em>e</em><em>r</em><em> </em><em>wou</em><em>ld</em><em> </em><em>c</em><em>o</em><em>s</em><em>t</em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>.</em><em>2</em><em>5</em>
Answer:
35% chose baseball or soccer
Step-by-step explanation:
baseball or soccer = 20% + 15% = 35%
_____
The categories add to 100%, so are mutually exclusive, as you expect when they are "favorite sport" categories. Hence the union of two of them will be their sum. (Otherwise, you'd have to subtract the amount by which the categories overlap.)
Answer: The real part is -6
The imaginary part is 2i
Step-by-step explanation:
