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1 year ago

13

What is the surface area of a sphere with radius 4?

1 answer:

mario62 [17]1 year ago

5 0

Answer: 64 units

Step-by-step explanation:

Remember, the formula to find surface area given radius is $4\pi r^2$ . Let's add in the given information:

4pi4^2 =

4pi16

64pi!

Hope this helps, please consider making me Brainliest.

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How would you describe the location of the solutions in the<br> coordinate plane?

zhannawk [14.2K]

Answer:

The coordinates of a point are a pair of numbers that define its exact location on a two dimensional plane. Recall that the coordinate plane has two axes at right angles to each other, called the x and y axis. The coordinates of a given point represent how far along each axis the point is located.

Step-by-step explanation:

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3 years ago

The width of a rectangle is 3x+5 and the length of the rectangle is 6x+10. Determine the ratio of the width to the perimeter.

Mashcka [7]

Answer:

1 : 6

Step-by-step explanation:

Calculate the perimeter

perimeter = 2(3x + 5) + 2(6x + 10) = 6x + 10 + 12x + 20 = 18x + 30

perimeter = 18x + 30 ← take out a common factor of 6 from both terms

= 6(3x + 5)

ratio of width : perimeter

= 1(3x + 5) : 6(3x + 5) ← divide both parts by (x + 5)

= 1 : 6

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3 years ago

Mary chooses an integer at random from 1 to 6. What is the probability that the integer she chooses is a prime number?

Tpy6a [65]

Answer: 3 out of 6

Step-by-step explanation:

The numbers she choses from are 1-6 therefore its out of 6

The prime numbers before six are two, three, and five.

therefore its 3/6 chance or 1/2 chance she picks a prime number.

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3 years ago

Plz help me, I'm too stupid to know this answer

katrin [286]

Answer:

The answer is the second one

Step-by-step explanation:

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3 years ago

Read 2 more answers

56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(

PIT_PIT [208]

There are 2 tangent lines that pass through the point

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

Explanation:

Given:

$y=\frac{x}{x+1}$

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

$y=m(x-1)+2$ $[1]$

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for $m$ :

$\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\$

$\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}$

$\frac{dy}{dx}= \frac{1}{(x+1)^2}$

$m=\frac{1}{(x+1)^2}$ $[2]$

Substitute equation [2] into equation [1]:

$y=\frac{x-1}{(x+1)^2}+2$ $[1.1]$

Because the line must touch the curve, we may substitute $y=\frac{x}{x+1}:$

$\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2$

Solve for x:

$x(x+1)=(x-1)+2(x+1)^2$

$x^2+x=x-1+2x^2+4x+2$

$x^2+4x+1$

$x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}$

$x=-2$ ± $\sqrt{3}$

$x=-2$ ± $\sqrt{3}$ <em> </em> $and$ $x=-2-\sqrt{3}$

There are 2 tangent lines.

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

8 0

2 years ago