(5^-2 ● 4^-4)^-2
you need to multiply tge power of tge outside the bracket with tge power inside the bracket to eliminate the power
= 5^4 ● 4^8
the answer is A
A=Y^6
B=7^4•n^5•m
C=y^4
D=t^4
Answer:
n=5
Step-by-step explanation:
Answer:
quotient: x^2 - 4x + 5
remainder: 8
Explanation:
1) Given
p(x) = x^3 - 2x^2 - 3x + 18
divisor: x + 2
2) Write the coefficients of p(x) in order:
1 -2 -3 18
3) dividing by x + 2 => run the division for x = - 2
4) division
| 1 -2 -3 +18
|
-2 | -2 +8 - 10
-----------------------------------
1 -4 +5 +8
The last digit is the remainder, the others are the coefficients of the quotient:
=>
quotient = x^2 - 4x + 5
remainder = 8
Answer:
8
Step-by-step explanation:
