Question

The rate constant for this zero-order reaction is 0.0270 M s^-1 at 300 C. How long (in seconds) would it take for the concentration of A to decrease from 0.780 M to 0.220 M?

Answer 1

Answer:

t = 20.74 sec

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t] =[A_0] -kt$

Where,  

$[A_t]$ is the concentration at time t  = 0.220 M

$[A_0]$ is the initial concentration  = 0.780 M

k is the rate constant = 0.0270 M s⁻¹

So,  

$0.220 =0.780 -0.0270\times t$

t = 20.74 sec