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3 years ago

Can a radical ever be rational?

Mathematics

2 answers:

Papessa [141]3 years ago

7 0

A radical can some times be a rational dependes on the numbers

Anon25 [30]3 years ago

6 0

Sure. Here's an example.

$\sqrt{\dfrac{49}{81}}=\dfrac{7}{9}$

Another one might look like this. $\sqrt[4]{16} = 2$

And just one more

$\sqrt[3]{8000} = 20$

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Explain how to find 40x80 using mental math

nadya68 [22]

so 40 * 80 = 3,200

4 * 8 = 32

Then add the two 0's to the end

so 3,200

5 0

3 years ago

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If a restaurant bills totals $85, what amount should be left as a 15$ tips A. $97.75 B. $11.90 C.$12.25 D. $12.75

Nata [24]

If the total bill is $85, and you want to leave a 15% tip, then you can calculate it as follows:

85 * 15%

= 85 * 15/100

= 85 * 0.15

= 12.75

The amount that should be left as a tip is D. $12.75.

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4 years ago

I need help asap!!!

lara [203]

Answer: 12

Step-by-step explanation:

You would take 3+5=8

And then 20-8=12

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3 years ago

Line segment AB has endpoints A(3, -7) and B(-9,-5). Find the equation of the perpendicular bisector

kupik [55]

Answer:

y = 6x + 12

Step-by-step explanation:

We require the midpoint M and slope of AB

Using the midpoint formula, then

M = [ $\frac{1}{2}$ (3 - 9) , $\frac{1}{2}$ (- 7 - 5) ] = (- 3, - 6 )

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = A(3, - 7) and (x₂, y₂ ) = B(- 9, - 5)

m = $\frac{-5+7}{-9-3}$ = $\frac{2}{-12}$ = - $\frac{1}{6}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{1}{6} }$ = 6

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 6 , thus

y = 6x + c ← is the partial equation

To find c substitute M(- 3, - 6) into the partial equation

- 6 = - 18 + c ⇒ c = - 6 + 18 = 12

y = 6x + 12 ← equation of perpendicular bisector

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3 years ago

4*1 divided by 9*8 equals

kkurt [141]

The answer is 1/18 for the equation

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3 years ago

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