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3 years ago

A bowl contained 19.4 grams of salt. Then, Greg poured in another 56.24 grams. How much salt does the bowl contain now?

Mathematics

2 answers:

Ludmilka [50]3 years ago

7 0

Answer:

75.64

Step-by-step explanation:

add them

Elanso [62]3 years ago

7 0

Answer:

75.64

Step-by-step explanation:

Add the two amounts together to determine the amount of salt in the bowl

19.4+56.24

Make sure to line up the decimals

19.4

56.24

-----------

75.64

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IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

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⇒ $sinx = 2 (1-sin^2x)-1$

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⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

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Now , General Solution is given by :

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Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

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Answer:

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Step-by-step explanation:

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