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Bess [88]
3 years ago
7

In a titration experiment, how many moles of naoh will be required to completely neutralize 1 mole of nitric acid?

Chemistry
2 answers:
katrin [286]3 years ago
4 0

Answer:

One mole

Explanation:

The balanced chemical equation is

<u>1</u>NaOH + <u>1</u>HNO₃ ⟶ NaNO₃ + H₂O

<u>1</u> mol       <u>1</u> mol

The coefficients in front of the formulas tell you the amount of something that reacts with an equivalent amount of something else.

In this reaction, 1 mol NaOH reacts with 1 mol HNO₃.

Doss [256]3 years ago
4 0

The number of moles of NaOH required to neutralize {\text{HN}}{{\text{O}}_{\text{3}}} of is \boxed{{\text{1}}\;{\text{mole}}}.

Further explanation:

<u>Neutralization reaction: </u>

It is the reaction that occurs between an acid and a base in order to form salt and water. It is named so as it neutralizes the excess amount of hydrogen or hydroxide ions present in the solution. It is used to decrease the acidity in the stomach, wastewater treatment, antacid tablets, and to control the pH of soil.

Titration:

It is a laboratory technique to determine the concentration of an unknown solution with the help of a known concentration. The known solution (titrant) is added from the burette to a known quantity of unknown solution (analyte).

{\text{HN}}{{\text{O}}_3} is a strong monoprotic acid and {\text{NaOH}} is also a strong base. The titration between {\text{HN}}{{\text{O}}_3} and {\text{NaOH}} would result in the following neutralization reaction. The neutralization reaction between {\text{HN}}{{\text{O}}_3} and {\text{NaOH}} is as follows:

 {\text{HN}}{{\text{O}}_3} + {\text{NaOH}} \to {\text{NaN}}{{\text{O}}_3} + {{\text{H}}_2}{\text{O}}

Since both acids and bases are strong and therefore complete neutralization occurs. The salt and water are formed as products. So {\mathbf{1}}\;{\mathbf{mole}} of {\text{HN}}{{\text{O}}_3} will be neutralized by {\mathbf{1}}\;{\mathbf{mole}} of {\text{NaOH}}.

Learn more:

1. Calculate volume of   required to titrate at equivalence point: brainly.com/question/10691070

2. What will be pH when monoprotic acid and base is titrated: brainly.com/question/3168961

Answer details:

Grade: High school

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Neutralization reaction, HNO3, NaOH, monoprotic, strong, acid, base and titration.

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IceJOKER [234]

<u>Concepts used:</u>

1 mole of an element or a compound has 6.022 * 10²³ formula units

So, we can say that: <em>Number of formula units = number of moles * 6.022*10²³</em>

number of moles of an element or a compound = given mass/molar mass

<u>__________________________________________________________</u>

<u>003 - </u><u>Number of CaH₂ formula units in 6.065 grams</u>

Number of Moles:

We know that the molar mass of CaH₂ is 42 grams/mol

Number of Moles of CaH₂ = given mass/molar mass

Number of moles = 6.065 / 42

Number of moles = 0.143 moles

Number of Formula units:

Number of formula units = number of moles * 6.022*10²³

= 0.143 * 6.022 * 10²³

= 0.86 * 10²³ formula units

__________________________________________________________

<u>004 </u><u>- Mass of 6.34 * 10²⁴ formula units of NaBF₄</u>

Number of Moles:

We mentioned this formula before:

<em>Number of formula units = number of moles * 6.022*10²³</em>

Solving it for number of moles, we get:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variable

Number of moles = 6.34 * 10²⁴ / 6.022*10²³

Number of moles=  10.5 moles

Mass of 10.5 moles of NaBF₄:

Molar mass of NaBF₄ = 38 grams/mol

Mass of 10.5 moles = 10.5 * molar mass

Mass of 10.5 moles = 10.5 * 38

Mass = 399 grams

__________________________________________________________

<u>005</u><u> - Number of moles in 9.78 * 10²¹ formula units of CeI₃</u>

Number of Moles:

We have the formula:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variables

Number of Moles = 9.78 * 10²¹ / 6.022*10²³

Number of Moles = 1.6 / 10²

Number of Moles = 1.6 * 10⁻² moles   OR   0.016 moles

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Explanation:

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Answer: 6.48m/s

Explanation:

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