In a titration experiment, how many moles of naoh will be required to completely neutralize 1 mole of nitric acid?

Chemistry

2 answers:

katrin [286]3 years ago

4 0

Answer:

One mole

Explanation:

The balanced chemical equation is

1NaOH + 1HNO₃ ⟶ NaNO₃ + H₂O

1 mol 1 mol

The coefficients in front of the formulas tell you the amount of something that reacts with an equivalent amount of something else.

In this reaction, 1 mol NaOH reacts with 1 mol HNO₃.

Doss [256]3 years ago

4 0

The number of moles of NaOH required to neutralize ${\text{HN}}{{\text{O}}_{\text{3}}}$ of is $\boxed{{\text{1}}\;{\text{mole}}}$ .

Further explanation:

Neutralization reaction:

It is the reaction that occurs between an acid and a base in order to form salt and water. It is named so as it neutralizes the excess amount of hydrogen or hydroxide ions present in the solution. It is used to decrease the acidity in the stomach, wastewater treatment, antacid tablets, and to control the pH of soil.

Titration:

It is a laboratory technique to determine the concentration of an unknown solution with the help of a known concentration. The known solution (titrant) is added from the burette to a known quantity of unknown solution (analyte).

${\text{HN}}{{\text{O}}_3}$ is a strong monoprotic acid and ${\text{NaOH}}$ is also a strong base. The titration between ${\text{HN}}{{\text{O}}_3}$ and ${\text{NaOH}}$ would result in the following neutralization reaction. The neutralization reaction between ${\text{HN}}{{\text{O}}_3}$ and ${\text{NaOH}}$ is as follows:

${\text{HN}}{{\text{O}}_3} + {\text{NaOH}} \to {\text{NaN}}{{\text{O}}_3} + {{\text{H}}_2}{\text{O}}$

Since both acids and bases are strong and therefore complete neutralization occurs. The salt and water are formed as products. So ${\mathbf{1}}\;{\mathbf{mole}}$ of ${\text{HN}}{{\text{O}}_3}$ will be neutralized by ${\mathbf{1}}\;{\mathbf{mole}}$ of ${\text{NaOH}}$ .