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Nutka1998 [239]
3 years ago
6

Practice: Determine the products, balance the

Chemistry
1 answer:
Anna11 [10]3 years ago
4 0

1. Inorganic combustion

2. Organic combustion

<h3>Further explanation</h3>

Given

The chemical equations

Required

Balanced equation

Solution

Organic compounds have the characteristic that there is a chain of carbon atoms, while inorganic does not have a chain of carbon atoms

The reaction of a substance with oxygen is called a combustion reaction

Complete combustion of carbon compounds will get CO₂ gas, whereas if it is not complete it will produce CO gas

So Organic : contain a carbon atom (and often a hydrogen atom)

1. Ca + O₂ ⇒ CaO₂

Inorganic combustion⇒does not contain carbon

2. C₃H₂O + 3O₂ → 3CO₂ + H₂O

Organic combustion

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Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
4 years ago
Periodic Table High School Reference Sheet
Ira Lisetskai [31]
I believe it should be B
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