Answer is: thermal conductuction.
Thermal conductuction is the transfer of heat<span> through physical contact. </span>Thermal conduction<span> is the transfer of heat</span> by microscopic collisions of particles. <span>Heat spontaneously flows from a hotter to a colder body.
</span>The process of heat conduction depends on four basic factors: the temperature gradient<span>, the cross section of the </span>materials<span> involved, their path length and the properties of those materials.</span>
Yo sup??
Let the percentage of K-39 be x
then the percentage of K-40 is 100-(x+0.01)
We know that the net weight should be 39.5. Therefore we can say
(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5
(since we are taking it in percent)
39*x+40*(100-(x+0.01))+38*0.01=3950
39x+4000-40x-0.4+0.38=3950
2x=49.98
x=24.99
=25 (approx)
Therefore K-39 is 25% in nature and K-40 is 75% in nature.
Hope this helps.
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Answer:
No photoelectric effect is observed for Mercury.
Explanation:
From E= hf
h= Plank's constant
f= frequency of incident light
Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23
f= 11×10^14 Hz
The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface
I think the answer is 2Mg + H2O4 = Cu12O4 + 2H
I’m really not sure though so it might be wrong… I’m not the best at balancing equations lol
