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3 years ago

Which phrase is equivalent to the expression (17×4)−35?

Mathematics

1 answer:

Elan Coil [88]3 years ago

4 0

Answer:

-2380

Step-by-step explanation:

you first multiply 17 by 4

next multiply 68 by 35

you get 2380

finally add a negative sign in front of it

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A 45-year-old client diagnosed with colon cancer states, "I do not want any treatment. I have not seen any family members in 25

Kruka [31]

Answer:

3,2,1,4

Step-by-step explanation:

I am a loner, I have not seen any of my family in 25 years, beside, i will decide when and how i want to die. I do not want any treatment.

7 0

3 years ago

Read 2 more answers

the total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib. if the weight of the bag of sugar is 1.4 Ib, what is the we

baherus [9]

0.4 lbs each.

<h3>Further explanation</h3>

<u>Given: </u>

The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
The weight of the bag of sugar is 1.4 Ib

<u>Question: </u>

What is the weight of each piece of butter?

<u>The Process: </u>

The two steps for obtaining the weight of each piece of butter are as follows:

<u>Step-1:</u> the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

$\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }$

<u>Step-2:</u> the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

$\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Let's also consider the following quick steps.

<u>Quick steps: </u>

$\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Therefore, the weight of each piece of butter is 0.4 lbs.

<h3>Learn more </h3>

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Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

5 0

2 years ago

Read 2 more answers

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago

Is −4[3(x−7)] and 6(14−2x) equiviant

Paraphin [41]

Answer:

Yes.

Step-by-step explanation:

Set the equations equal to each other to determine their equality.

-4[3(x - 7)] = 6(14 - 2x)

Distribute the 3 and the 6 into their respective parenthesis.

-4[3x - 21] = 84 - 12x

Distribute the -4 into the brackets.

-12x + 84

Rearrange the equations.

84 - 12x = 84 - 12x

Since the equations come out to be the same thing on both sides so that any value satisfies it, the equations are equivalent.

4 0

2 years ago

Terri's teacher gives her the equation 3(5)^x=127-2x, and tells her that she will not know how to solve it algebraically. Explai

kirza4 [7]

$f(x)=3\cdot5^x\ \ \ and\ \ \ g(x)=127-2x\\\\f(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x\approx2.3043\\\\the\ graph\ in\ annex$

8 0

2 years ago