Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Answer:
Option (2)
Step-by-step explanation:
Given expression is
÷ 
We further simplify this expression,
÷
= 
= 
= 
Therefore,
will be the quotient of the given expression.
and
for which the given expression is not defined.
Option (2) will be the answer.
Answer:
Step-by-step explanation:
What is y?
The degree is "4" and the number of terms is "1"
Answer:
33.3333333333
Step-by-step explanation: