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irina [24]
3 years ago
9

Suppose you choose a marble from a bag containing 3 red marbles, 5 white marbles, and 4 blue marbles. You return the first marbl

e to the bag and then choose again. Find P(red and blue)
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
6 0

Answer:

P(red and blue) = 0.1667

Step-by-step explanation:

Let A represent choosing a red marble, there are 3 red marbles

Let B represent choosing a blue marble, there are 4 blue marbles

There are 12 total marbles

Then...

P(A) = 3/12

P(B) = 4/12

choosing the first one, then replacing means the first choice has no effect on the probabilities of the second choice, so the situation is independent.  

When calculating the probability of independent events, you multiply the probabilities together.  There are 2 scenarios where we can get a red and blue marble..

Choosing a red, then a blue marble, the probability is

(3/12)( 4/12) = 12/144 = 1/12

Choosing a blue, then a red marble, the probability is

(4/12)(3/12) = 12/144 = 1/12

So we have a

(1/12) + (1/12) = 2/12 = 1/6 chance for that to happen, to

P(A and B) = 1/6 = 0.1667

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Answer:

system of equations are

y=53x + 10, y=55x

Step-by-step explanation:

y=mx+b where x is the number of tickets purchased and y is the total cost.

We need to frame the equation for each option

Option 1: $53 for each ticket plus a shipping fee of $10

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Step-by-step explanation:

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Algebra 1 question : Solve for x : 3 - 5x + 6 = 14x - 32 + 10(2-x)
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Hi there!

3 - 5x + 6 = 14x - 32 + 10(2 - x)
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