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valentinak56 [21]

4 years ago

12

What is the domain of the function f(x) = x + 2 ? a. all real numbers greater than -2 b. all real numbers greater

than 2 c. all real numbers

1 answer:

dsp734 years ago

3 0

The domain of the function is represented by option C. All real numbers.

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Find the ratio a:c if <br>a:b = 1:2, b:d = 4:5, d:c = 3:1<br>

Makovka662 [10]

Answer:

a : c = 6 : 5

Step-by-step explanation:

Expressing the ratios in fractional form, then

$\frac{a}{c}$ = $\frac{a}{b}$ × $\frac{b}{d}$ × $\frac{d}{c}$ = $\frac{1}{2}$ × $\frac{4}{5}$ × $\frac{3}{1}$ = $\frac{12}{10}$ = $\frac{6}{5}$

Thus a : c = 6 : 5

3 0

3 years ago

Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)

Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

cosθ = ¹/₂[e^jθ + e^(-jθ)]

b. We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Subtracting both equations, we have

e^jθ = cosθ + jsinθ

-

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)

Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

sinθ = ¹/₂[e^jθ - e^(-jθ)]

4 0

4 years ago

X=c/r make the r as a subject

kupik [55]

Answer:

r = c/x

Step-by-step explanation:

7 0

3 years ago

Graph the line that passes through the points ( 0 , − 4) and (−5,2) and determine the equation of the line.

Eduardwww [97]

Answer:

i am highly sorry but there is no graph for me to help you with on this site :(

but to help you the X line always comes first for example the (-5,2) the -5 would be on the X line. I really hope that this help. :)

7 0

3 years ago

The play director spent 190190190190 hours preparing for a play. That time included attending 35353535 rehearsals that took vary

Genrish500 [490]

Answer:

The equation above represents the total time the play director spent preparing for a play.

Step-by-step explanation:

The time spent by the play director for preparing for a play is, 190 hours.

Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.

Let the varying amounts of time be denoted by, <em>x</em>.

The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.

The equation provided is:

$35x+\frac{3}{4}=190$

The equation above represents the total time the play director spent preparing for a play.

7 0

4 years ago