Which of the following is considered to be an accrued expense

Mathematics

2 answers:

ipn [44]2 years ago

8 0

Answer:

Oh, edit your question and add the file, and when you add the file, I will edit this and help.

Step-by-step explanation:

fomenos2 years ago

5 0

Answer:where

Step-by-step explanation:

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AP calculus HW Need help on #61

Yuki888 [10]

Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x

Crossing the 1s , the 2xs, and the x^2s out, we get

(2x</span>∆x+∆x^2-2∆x)/<span>∆x

Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.

Making the limit of </span><span>∆x=0, we get 2x-2.</span>

7 0

3 years ago

What is the equation of this line in standard form? 8x−7y=−25 8x−9y=23 8x−9y=−23 9x−8y=23 Number graph ranging from negative fiv

Gnoma [55]

Answer:

The equation of line is:

$8x-9y=-23$

Step-by-step explanation:

We are given that a graph is a that passes through two points:

$(-4,-1)$ and $(\dfrac{1}{2},3)$

We know that the equation of line passing through two points:

$(a,b)$ and $(c,d)$ is given by:

$y-b=\dfrac{d-b}{b-a}\times (x-a)$

Here we have:

$(a,b)=(-4,-1)$ and $(c,d)=(\dfrac{1}{2},3)$

Hence, the equation of line is:

$y-(-1)=\dfrac{3-(-1)}{\dfrac{1}{2}-(-4)}\times (x-(-4))\\\\y+1=\dfrac{3+1}{\dfrac{1}{2}+4}\times (x+4)\\\\y+1=\dfrac{4}{\dfrac{9}{2}}\times (x+4)\\\\y+1=\dfrac{4\times 2}{9}\times (x+4)\\\\y+1=\dfrac{8}{9}\times (x+4)\\\\9\times (y+1)=8\times (x+4)\\\\9y+9=8x+8\times 4\\\\9y+9=8x+32\\\\8x-9y=9-32\\\\8x-9y=-23$