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ExtremeBDS [4]
3 years ago
10

Find the distance between each pair of points

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0
(C,D) is 5 units

(E,F) is 4 units

(A,B) is 6units

(G,H) is 3 units
larisa [96]3 years ago
6 0

Answer:

CD is 5 units

EF is 4 units

AB is 6 units

GH is 3 units

Step-by-step explanation:

It's simply subtracting and adding!

Hope that helps!

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In ΔCDE, the measure of ∠E=90°, the measure of ∠C=75°, and CD = 5.8 feet. Find the length of EC to the nearest tenth of a foot.
bearhunter [10]

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Find sec s if tan s = 3/4 and s is in quadrant I.
LUCKY_DIMON [66]

Answer:

4/3.

Step-by-step explanation:

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3 years ago
el perimetro de un terreno rectangular es de 170m y su area es de 170^2hallar la medida de sus lados con ecuacion cuadratica
Blizzard [7]

Answer:

Acá tenemos un sistema de ecuaciones.

El perímetro de un rectángulo es:

2*A + 2*L = 170m

donde A es el ancho y L es el largo.

Y el área del rectángulo es:

A*L = 170m^2.

Entonces, el primer paso es aislar una de las variables en una de las ecuaciones, yo voy a aislar A en la segunda:

A = 170m^2/L.

Ahora reemplazo eso en la primera ecuación y la resuelvo para L.

2*( 170m^2/L.) + 2*L = 170m.

340m^2 + 2*L^2 = 170m*L

ahora tenemos una ecuación cuadrática:

2*L^2 - 170m*L + 340m^2 = 0.

Las soluciones se pueden obtener usando la formula de Bhaskara:

L = \frac{+170 +- \sqrt{170^2 -4*340*2}  }{2*2} = \frac{170 +-161.8}{4}

Entonces las soluciones son:

L = (170 + 161.8)/4 = 82.95m

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Entonces, si tomamos L = 82.95m, tenemos A = 4.1 m

y el área es:

A*L = 4.1m*82.95m = 170m^2

3 0
3 years ago
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