Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
I do not understand the answers can you list them better please?
Answer:
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−
3
/2
Precalculus, Matrix
Rearrange terms, Combine multiplied terms into a single fraction, distribute, Multiply all terms by the same value to eliminate fraction denominators, Multiply all terms by the same value to eliminate fraction denominators
. Cancel multiplied terms that are in the denominator
. Multiply the numbers
. Add 4 to both sides of the equation
. Simplify.
Divide both sides of the equation by the same term . Simplify
Answer:
Attached
Step-by-step explanation:
Just for your reference, this question will get unlimited number of solutions, attached is a few examples I calculated from Excel. Have fun to pick one or create one to be your favorite.
Adults pay = $33.60
Children pay = $16.80 (it's half price but if they take a round trip it's double the price. Therefore it's $16.80) then multiply both by two and add them together.
2 ($33.60+$16.80) = $100.80
