Answer:
u8uij
Step-by-step explanation:
jbjkh
The classify triangle ABC is the acute,obtuse,right,or equilateral.
When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
9514 1404 393
Answer:
23.44
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relation ...
Tan = Opposite/Adjacent
tan(38°) = x/30
x = 30·tan(38°) ≈ 23.4386
x ≈ 23.44
6y+11=23
-11 -11
6y=12
/6 /6
y=2
5x-55
