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prisoha [69]
3 years ago
5

Solve 1/2(-4x+6)=1/3(9x-24)

Mathematics
2 answers:
CaHeK987 [17]3 years ago
5 0
Solve parenthesis first. 1/2(-4x+6). That means you gonna have to distribute .
1/2 of -4x would be -2x and 1/2 of 6 is 3. so -2x+3.
1/3(9x-24) so 3x-8. 
-2x+3+3x-8. combine like terms. so it would be x(or 1x if you perfer it) . x-5
irga5000 [103]3 years ago
3 0
                   x = 11/5 = 2.200  hope this helps

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son4ous [18]

Answer:

y=x2

I got it solved! tell me if it helped

4 0
3 years ago
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Determine the solution and the reasoning that justifies the solution to the systems of equations.
Lena [83]

Answer:

<u>Option 2</u>

(2,8), because the graph of the two equations intersects at this point

Step-by-step explanation:

Just looking at the graph, you can tell that the point (2,8) is where the two lines intersect.

Hope this helped! :)

8 0
3 years ago
Can anyone help me with this, I’ll give out brainliest. NO LINKS.
Sliva [168]

Answer:

89.132 inch

Step-by-step explanation:

“this shape is made up of one half-circle attached to a square with side lengths 16 inches. You can use 3.14 as an approximation.”

so, the square has a perimeter of 16 inch, four sides that will be 64 inch

then the half circle rule of perimeter of half circle: πr + 2r

=> perimeter of semicircle = π * 8 +2 * 8 = 41.132 inch

<em>without the bottom line of half circle= 41.132 -16 = 25.133 inch</em>

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So total 25.133 + 64 =89.132 inch

have a great day and nc question

4 0
2 years ago
PLEASE ANSWER QUICKLY AND HELP ME!! THANK YOU SO MUCH!!
coldgirl [10]
Hello there!

To start off this problem, let's replace f(x) with x in the equation. This gives us the following.

x= \dfrac{3}{4} x+12

Subtract 3/4*x from both sides.

x- \dfrac{3}{4} x=12

\dfrac{4}{4} x-\dfrac{3}{4}x=12

\dfrac{1}{4} x=12

Now, multiply both sides by 4 to eliminate the fraction on the left side.

x=12*4=48

Your answer is B. Hope this helps! :)
5 0
3 years ago
-4/2/5 = -3/1/5 + 7/10g
ludmilkaskok [199]

Answer:

g=12/7

Step-by-step explanation:

3 0
3 years ago
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