Answer:
IQR = 3
Step-by-step explanation:
Interquartile range, which is abbreviated as IQR, is just the difference between the upper quartile (where the box ends) and the lower quartile (where the box starts). AS it is given in the question that that box starts from 4 and ends at . The interquartile range IQR is simply:
IQR = 7 - 4 = 3
The values of data are usually clustured around some central value. Interquartile range tells us how spread out these middle values. It also tells when some values are too far from the central value. The values which are too far are also termed as outlier values
4x=36－5x
x=4
The perimeter of the square=4x4×4
=64
Answer:
First lets find the area of the bottom circle:
7.2 is your radius so:
7.2^2 = 51.84 the reason why you square your radius is because thats apart of the formula when finding the are of a circle.
lets continue:
51.84 x 3.14(pi) = 162.7776
Now we need to find the area of the round surface but first we need to find the circumference of one circle and multiply it by the height.
2 x 3.14 x 7.2 = 45.216
Now lets multiply it by the height:
45.216 x 17 = 768.672
Now lets add both areas:
768.672 + 162.7776 = 931.4496 dont forget to round to the nearest hundredths place! 931.4496 rounded up = 931.45 square meters is your answer.
1)
4m^4 - 5m^2
answer is D. last choice
2)
= 7x - 35 + 3x - 9
------------------------
(x - 3)(x-5)
= 10x - 44
--------------------
(x - 3)(x-5)
answer is B.
