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2 years ago

Find x in each triangle

Mathematics

2 answers:

MaRussiya [10]2 years ago

8 0

Answer:

Step-by-step explanation:

BY PYTHAGORAS THEOREM

Gwar [14]2 years ago

3 0

Answer:

x = 15 ft

Step-by-step explanation:

using the Pythagorean theorem:

x² = 17² - 8² = 289 - 64 = 225

x = √225 = 15

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If a 5 ft tall man cast an 8 ft long shadow at the same time a tree cast a 24 ft long shadow, how tall is the tree?

Taya2010 [7]

Answer:

15 feet

Step-by-step explanation:

We have 2 similar right triangles with legs height and length of shadows.

height of men : length of shadows of the man = height of tree : length of shadows of the tree

5 : 8 = x : 24

8x = 5* 24

x = 5*24/8 = 15 (feet)

5 0

3 years ago

Read 2 more answers

Una fábrica envasadora recibe diariamente distintos tipos de aceite en las siguientes cantidades: 195 l, 275 l, 315 l, 460 l y 5

BabaBlast [244]

Answer:

Se calcula el maximo comun divisor.

195/5 = 39

275/5 =55

315/5 =63

460/5= 92

525/5 =105

Se deben utilizar 354 garrafas

Step-by-step explanation:

Descomponemos cada número en factores primos.

Después, señalamos los factores comunes.

A continuación, en cada uno de los comunes, escogemos el factor con menor exponente.

Y por ultimo, multiplicamos los factores elegidos.

195 3 275 5 315 3 460 2 525 3

65 5 55 5 105 3 230 2 175 5

13 13 11 11 35 5 115 5 35 5

1 1 7 7 23 23 7 7

1 1 1

3 0

3 years ago

Dr. Wong has a table of data in her veterinary office that shows the average lifespans and weights of several popular dog breeds

SIZIF [17.4K]

Answer:

Step-by-step explanat

disculpa pero me voy a robar tus puntos no es nada personal

6 0

2 years ago

Can someone help me in #66

VladimirAG [237]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
$

$\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]$

$\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)$

6 0

3 years ago

Mark is going to an awards dinner and wants to dress appropriately. He had one blue shirt, one white dress shirt, one black dres

lidiya [134]

Answer:

All the four statements are true , which are -

(A) The subset contains contains of all the outfits that have grey slacks .

(B) The subset contains contains of all the outfits that have grey slacks and red tie .

(C) The subset contains contains of all the outfits that have grey slacks and blue shirt .

(D) The subset contains contains of all the outfits that do not have black slacks .

Step-by-step explanation:

We are given with Outfit 2 , 4 and 6

Outfit 2 - Blue grey red

Outfit 4 - White grey red

Outfit 6 - Black grey red

(A) Since only 2,4, and 6 contain grey slacks, and no other outfit contains grey slacks, those are the subsets that contain grey slacks. Thus , this statement is true .

(B) Just outfits 2, 4, and 6 have grey slacks and a red tie, proving the statement. Other clothes do not include grey slacks and a red tie; they may include a red tie but not both grey slacks and a red tie. Hence , the statement is true .

(C) Since the outfit 2 has grey slacks and a blue shirt, the statement is correct; no other outfit has both grey slacks and a blue shirt. Therefore , this statement is also correct .

(D) The argument is correct since all of the subsets contain grey slacks and no black slacks.

Hence , all the options A , B , C , D are correct and describes the subset .

The given question is incomplete , the complete question is attached here -

3 0

3 years ago