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vitfil [10]
3 years ago
11

Someone anyone please

Mathematics
1 answer:
Lisa [10]3 years ago
5 0

Answer:

9 or 3^2

Step-by-step explanation:

3^3×3^3=729

3^4=81

729/81 = 9 = 3^2

You might be interested in
Prove that 25^11−5^19 is divisible by 31.
SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

5^19*5^3 - 5^19*5^0

5^19(5^3 - 5^0)

5^19(125 - 1)

5^19*(124)

At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4

Since 31 is a factor of the original expression, this means the original expression is divisible by 31.

4 0
4 years ago
I need help pleaseeeeeee
soldi70 [24.7K]

Answer:

For a triangle to be equiangular all its three interior angles must be equal, that is, each angle should measure 60˚.

Step-by-step explanation:

5 0
3 years ago
Car travels and average speed of 48 miles per hour how long does it take to travel 180 miles?
Neporo4naja [7]

speed =48mph

distance = 180 miles

we know that

time = distance / speed

time=\frac{180}{48} hours

time=3.75 hours..........Answer

5 0
3 years ago
Read 2 more answers
Does it matter if you add azero when you divide a dcimal.
Brilliant_brown [7]
No, it won't change the outcome.
3 0
4 years ago
Read 2 more answers
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
4 years ago
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