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VMariaS [17]
3 years ago
13

Ten more shoes than Rubens

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

What Do You Mean

Step-by-step explanation:

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The base of a triangular pyramid has an area of 20 square feet. The height of the pyramid is 36 feet. The volume of the pyramid
fenix001 [56]

Answer:

so what's the question? i'm a bit confused..

Step-by-step explanation:

7 0
2 years ago
What is the simplified polynomial and the value
Elanso [62]

The simplified polynomial is; xy(x²y - xy² +1) and; the value when x=-3 and y=2 is; -186

From the polynomial given;

  • x²yxy -xy²xy +xy.

The polynomial can be factorised to yield a simpler form as follows;

  • xy(x²y - xy² +1).

This is so because, xy is a common factor.

The value is therefore;

  • (-3×2)((-3)²2 - (-3×2²) +1)

  • -6(18+12+1)

= -186

Read more on polynomials;

brainly.com/question/2833285

7 0
2 years ago
Perform the indicated operation.<br> f(n) = 4n - 5, g(n) = n^2 - 5<br> Find: (f - g) (n)
Alex777 [14]

Hi there!

\large\boxed{-n^2 + 4n}

Begin by evaluating f - g:

4n - 5 - (n² - 5)

Simplify:

4n - 5 - n² + 5  = 4n - n²

Or it can be written as -n² + 4n to match the first answer choice.

3 0
2 years ago
Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
Which algebraic expression is a polynomial?
lisov135 [29]

Answer:

3m²n

Step-by-step explanation:

polynomials have a degree of 2 or more.

4 0
2 years ago
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