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3 years ago

Does the equation below represent a relation, a function, both a relation and a function, or neither a relation nor function

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

Answer:

A. neither a relation nor a function

Step-by-step explanation:

A relation between two sets is a collection of ordered pairs containing one object from each set.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Quadratic equations are not functions. Quadratic equations are not a function because they touch two points that is on the same y-axis. Furthermore, if they are two points that have the same x axis, then it is not a function either. It doesn't have a relation either because there are two outputs that are the same by the x axis for 3x^2 - 9x + 20. Those are x = 1 and x = 2. For proof, you can plug both of them in.

3(1)^2 - 9(1) + 20 = 14

3(2)^2 - 9(2)+ 20 = 14

Both answers have 14 as the y-axis/output. This proves that this quadratic equation is not a relation either. Therefore, this equation is neither a relation nor a function.

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The Garden Task

Igoryamba

If the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:

the perimeter = 24 ft
the area = 36 sq. ft
if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
if the area of the garden is doubled, the area of the new garden = 72 sq. ft

Recall:

A square has equal side lengths
Perimeter of a square = 4(side length)
Area of a square = $(side $ length)^2$

Given:

Perimeter of square (P) = $(14x - 32) $ ft$

Side length (s) = $(x + 2) $ ft$

First, let's find the value of x by creating an equation using the perimeter formula:

Perimeter of a square = 4(side length)

Plug in the values

$(14x - 32) = 4(x + 2)$

Solve for x

$14x - 32 = 4x + 8\\\\14x - 4x = 32 + 8\\\\10x = 40\\\\x = 4$

Find how much fencing would be needed (Perimeter of the fence):

Perimeter of the fence = $(14x - 32) $ ft$

Plug in the value of x

Perimeter of the fence = $14(4) - 32 = 24 $ ft$

Find the area of the garden:

Area of the garden = $(side $ length)^2$

Area = $(x + 2)^2$

Plug in the value of x

Area = $(4 + 2)^2 = 6^2 = 36 $ ft^2$

Find the perimeter if the garden size is doubled:

Perimeter of the new garden = 2 x 24 = 48 ft

Find the area if the garden size is doubled:

Perimeter of the new garden = 2 x 36 = 72 sq. ft

In summary, if the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:

the perimeter = 24 ft
the area = 36 sq. ft
if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
if the area of the garden is doubled, the area of the new garden = 72 sq. ft

Learn more here:

brainly.com/question/13511952

4 0

2 years ago

Solve the system of equations : y = x/2 , y = -x - 3 . You can use any method you wish for solving systems of equations. Check y

lorasvet [3.4K]

Answer:

x=−2 and y=−1

Step-by-step explanation:

Problem:

Solve y=x2;y=−x−3

Steps:

I will solve your system by substitution.

y=1/2x;y=−x−3

Step: Solve y= 1/2x for y:

Step: Substitute 1/2 x for y in y=−x−3:

y=−x−3

1/2x= =−x−3

1/2x+x=−x−3+x(Add x to both sides)

3/2x = -3

3/2x/3/2 = -3/3/2 (Divide both sides by 3/2)

x=−2

Step: Substitute −2 for x in y=1/2x:

y=1/2x

y=1/2(-2)

y=−1(Simplify both sides of the equation)

Answer:

x=−2 and y=−1

5 0

1 year ago

The radius of a cylindrical vessel is 7 cm and height is 1400 m . Find the cost of painting its inner curved surface area at the

Olegator [25]

Answer:

Cost = 616000 DHS per square centimetre.

Step-by-step explanation:

curved surface of a cylinder = 2 $\pi$ rh

r = 7 cm

h = 1400 m = 140000 cm

The outer curved surface area of the cylinder = inner curved surface area of the cylinder

The inner curved surface of the cylinder = 2 $\pi$ rh

= 2 x $\frac{22}{7}$ x 7 x 140000

= 2 x 22 x 1 x 140000

= 6160000

The inner curved surface of the cylinder is 6160000 square centimetre.

But, the cost of painting is at the rate of 10 DHS per square centimetre.

The inner curved surface of the cylinder = 6.16 x $10^{6}$ square centimetre.

cost of painting the inner curved surface area = $\frac{6.16*10^{6} }{10}$

= 616000 DHS per square centimetre

The cost of painting the inner surface is 616000 DHS per square centimetre.

6 0

2 years ago

Show work THEN the answer

inysia [295]

The answer is 1.7325

1x5=5
1x2=2
1x8=8
Add a zero
2x5=10
2x2=4
2x8=40
Add a Zero
All the answers to the next number will all be zero.

Add that all together.

8 0

3 years ago

1 All sides are congruent. Paralelogram Rhombus Rectangle Square

Amanda [17]

Answer:

Rhombus

Square

Step-by-step explanation:

Rhombuses and squares have sides that are always congruent.

8 0

2 years ago