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3 years ago

Does the equation below represent a relation, a function, both a relation and a function, or neither a relation nor function

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

Answer:

A. neither a relation nor a function

Step-by-step explanation:

A relation between two sets is a collection of ordered pairs containing one object from each set.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Quadratic equations are not functions. Quadratic equations are not a function because they touch two points that is on the same y-axis. Furthermore, if they are two points that have the same x axis, then it is not a function either. It doesn't have a relation either because there are two outputs that are the same by the x axis for 3x^2 - 9x + 20. Those are x = 1 and x = 2. For proof, you can plug both of them in.

3(1)^2 - 9(1) + 20 = 14

3(2)^2 - 9(2)+ 20 = 14

Both answers have 14 as the y-axis/output. This proves that this quadratic equation is not a relation either. Therefore, this equation is neither a relation nor a function.

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Will get brainliest What is the value of x?

kicyunya [14]

Answer:

x=135

Step-by-step explanation:

all the numbers need to add up to 180

7 0

3 years ago

The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. A

Montano1993 [528]

Answer: (14.4, 17.2)

Step-by-step explanation: We are to construct a 98% confidence interval for mean household usage of electricity.

We have been given that

Sample size (n) = 872

Sample mean (x) = 15.8

Population standard deviation (σ) = 1.8

The formulae that defines the 98% confidence interval for mean is given below as

u = x + Zα/2 × σ/√n...... For the upper limit

u = x - Zα/2 × σ/√n...... For the lower limit

Zα/2 = critical value for a 2% level of significance in a two tailed test = 2.33

By substituting the parameters we have that

For upper tailed

u = 15.8 + 2.33 × (1.8/√872)

u = 15.8 + 2.33 (0.6096)

u = 15.8 + 1.4203

u = 17.2

For lower tailed

u = 15.8 - 2.33 × (1.8/√872)

u = 15.8 - 2.33 (0.6096)

u = 15.8 - 1.4203

u = 14.4

Hence the 98% confidence interval for population mean usage of electricity is (14.4kwh, 17.2kwh)

4 0

3 years ago

A diver was 40 feet below the surface of the water. A fisherman was casting off a dock right above the diver that was 12 feet ab

Nesterboy [21]

Answer:

The answer is D.

Step-by-step explanation:

It is D because they cannot be negative feet away and if the fisherman is 12ft above water and the diver is 40ft below than 40 + 12 = 52. Hope this helps.

5 0

3 years ago

Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.

jek_recluse [69]

Answer:

$\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)$

Step-by-step explanation:

Let $X$ be a set of all students in your class. The set $X$ is the domain. Denote

$C(x) - ' \text{$x $ has a cat}'\\D(x) - ' \text{$x$ has a dog}'\\F(x) - ' \text{$x$ has a ferret}'$

$\mathbf{a)}$

Consider the statement 'A student in your class has a cat, a dog, and a ferret'. This means that $\exists x \in X$ so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)$

$\mathbf{b)}$

Consider the statement 'All students in your class have a cat, a dog, or a ferret.' This means that $\forall x \in X$ at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)$

$\mathbf{c)}$

Consider the statement 'Some student in your class has a cat and a ferret, but not a dog.' This means that $\exists x \in X$ so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

$\left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)$

$\mathbf{d)}$

Consider the statement 'No student in your class has a cat, a dog, and a ferret..' This means that $\forall x \in X$ none of the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

$\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)$