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Alex17521 [72]
3 years ago
15

Does the equation below represent a relation, a function, both a relation and a function, or neither a relation nor function

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

A. neither a relation nor a function

Step-by-step explanation:

A relation between two sets is a collection of ordered pairs containing one object from each set.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Quadratic equations are not functions. Quadratic equations are not a function because they touch two points that is on the same y-axis. Furthermore, if they are two points that have the same x axis, then it is not a function either. It doesn't have a relation either because there are two outputs that are the same by the x axis for 3x^2 - 9x + 20. Those are x = 1 and x = 2. For proof, you can plug both of them in.

3(1)^2 - 9(1) + 20 = 14

3(2)^2 - 9(2)+ 20 = 14

Both answers have 14 as the y-axis/output. This proves that this quadratic equation is not a relation either. Therefore, this equation is neither a relation nor a function.

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Paint costs $19.95 per gallon. Nicole needs 1.25 gallons to complete a painting project
ra1l [238]

Answer:

$25.00

Step-by-step explanation:

  1. Set up a proportion: \frac{19.95}{1} = \frac{x}{1.25}  
  2. Cross multiply, then divide: 19.95 × 1.25 = 24.9375, 24.9375 ÷ 1 = $24.9375
  3. Round your answer: $24.9375 → $25.00

I hope this helps!

8 0
3 years ago
BRAINLYST TO THE FRIST PERSON TO ANSWER
alina1380 [7]

Answer:

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Step-by-step explanation:

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3 years ago
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If Harrisen makes $10 an hour, how much will he make in a 40 hour work week?
ahrayia [7]
The answer would be 400$. This is because 40 x 10 = 400. 
3 0
4 years ago
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(-2, 4), (0, 2), (-1, 3), (4, -2) } The set of ordered pairs above:
NISA [10]
So what is the question
7 0
4 years ago
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Find the perimeter of the object <br><br> Help step by step please!
aliina [53]

Answer:

29.42 units

Step-by-step explanation:

<u>1) Find the perimeter around the semi-circle</u>

To do this, we find the circumference of the circle using the given diameter:

C=\pi d where d is the diameter

Plug in 6 as the diameter

C=\pi (6)\\C=6\pi

Divide the circumference by 2

\frac{6\pi }{2} \\= 3\pi

Therefore, the perimeter around the semi-circle is 3π units.

<u>2) Find the perimeter around the rest of the shape</u>

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

20+3\pi \\= 20+9.42\\= 29.42

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

3 0
3 years ago
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