Answer:
The options are:
A. Gravel
B. Sand
C. Silt
D. Clay
E. Mud
The answer is A. Gravel
Explanation:
Meiofauna are small benthic invertebrates which live in aquatic habitat. They are suited for both marine and fresh water environments.
Gravel aren’t tightly packed together in large quantities when compared with the other options such as sand, silt, clay, mud. This makes it possible for more aeration and the presence of more oxygen at the soft-bottomed intertidal community.
A myelinated axon has a sheath around it and a bore axon doesn't have it, it's open or exposed so to speak. T<span>he myelin is made up of fat and protein and works like insulation. these axons make up the white matter in the brain since it appears white. The sheath helps to keep the electrical current from leaving the axon and the myelin sheath provides a tract along which regrowth can occur. </span>
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
