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larisa [96]
2 years ago
13

Which equations have a leading coefficient of 3 and a constant term of –2? Check all that apply.

Mathematics
2 answers:
Svetllana [295]2 years ago
8 0
Answers are: choice A, choice C, choice E

Explanation: The leading coefficient is the number that is to the left of the term with the largest exponent, which in this case is 2. The term 3x^2 is the leading term with the coefficient of 3. This is why the leading coefficient is 3 for choice A, choice C, and choice E. Choice B has a leading coefficient of -3 so we can rule that out. Choice D has a leading coefficient of 3, but the constant term is NOT -2. Instead the constant term is +2, so we can rule out choice D as well. The other choices that haven't been eliminated all have 3x^2 somewhere in them, as well as the constant term -2. The other x term isn't relevant to the restrictions placed in the instructions. 

Phoenix [80]2 years ago
5 0

Answer:

a,c,e

Step-by-step explanation:

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(x+2y = 10<br> 16y=-3x+30
Harlamova29_29 [7]

Answer:

x = 10, y = 0

Step-by-step explanation:

x + 2y = 10

x = 10 - 2y <em>(</em><em>B</em><em>r</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>2</em><em>y</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>)</em>

16y = -3x + 30

16y = -3(10 - 2y) + 30 <em>(</em><em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>e</em><em> </em><em>x</em><em> </em><em>t</em><em>o</em><em> </em><em>1</em><em>0</em><em> </em><em>-</em><em> </em><em>2</em><em>y</em><em>)</em>

16y = -30 + 6y + 30 <em>(</em><em>E</em><em>x</em><em>p</em><em>a</em><em>n</em><em>d</em><em> </em><em>b</em><em>r</em><em>a</em><em>c</em><em>k</em><em>e</em><em>t</em><em>s</em><em>)</em>

10y = 0 <em>(</em><em>B</em><em>r</em><em>i</em><em>n</em><em>g</em><em> </em><em>y</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>)</em>

<u>y</u><u> </u><u>=</u><u> </u><u>0</u>

x = 10 - 2(0) <em>(</em><em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>e</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>0</em><em>)</em>

<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>0</u>

<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>0</u><u>,</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>0</u>

7 0
3 years ago
Which graph shows the equation v=4+2t
ehidna [41]
You need to give options for future reference
5 0
3 years ago
P= $1,000, t= 6, r= 11%, compounded annually (k = 1)​
kobusy [5.1K]

Answer:  well if p= $1000 and t=6 and r-11 %  then 6k+11=1000 then 11- 1000 is 6k=989 divide 6/ 164.83 i think

Step-by-step explanation:

8 0
3 years ago
According to the empirical rule, if the data form a "bell-shaped" normal distribution, ________ percent of the observations will
jekas [21]
According to empirical rule, the area under the normal distribution or "bell-shaped curve", when plotted as a function of the z-parameter can be defined in terms of percentages.
The z-parameter (or z-score) is defined as
z= \frac{x- \mu }{ \sigma }
where
x =  value of random variable,
μ = the mean,
σ = standard deviation,

The total area under the curve = 1.
The curve below shows that within 2 standard deviations from the mean, the total area under the curve is 95%  of the total area.



Answer: 95%

5 0
3 years ago
Solve : 2/3+(x)=3 <br> A)-4/3<br> B)-7/3<br> C)4/3<br> D)7/3
snow_tiger [21]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
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