<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
<em />
Answer:
it's rectangle...
Step-by-step explanation:
mark me brainliest
A) Subtract A and C from both sides:
B = 180-A-C
B) Divide both sides by p and t:
r = i /pt
C) Divide both sides by PIh
r^2 = V/pih
Take the square root of both sides:
r = SQRT(V/pih)
D) Subtract ax from both sides:
by = c-ax
Divide both sides by b:
y = (c-ax)/b
Answer: 90 more tickets
Step-by-step explanation:
230 - 50 = 180
180 divided by 2 = 90 tickets
