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NeTakaya
3 years ago
7

Find the common ratio and the next term for the sequence shown. Express your answers as fractions or as decimals.

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0
The common ratio of the sequence is calculated by dividing the second term by the first term or dividing the third term by the second term. That is,
                               r = 250 / 333 = 0.75
or                            r = 187 / 250 = 0.748 = 0.75
To get the next term, we multiply 187 by 0.75 giving us an answer of 140.25 or 141. 
tresset_1 [31]3 years ago
5 0

Answer: The common ratio is 0.750750....

and the next term is 140.390390.....

Step-by-step explanation:

Since we have given that

333,250,187,....

First we need to find the "Common ratio":

r=\frac{a_2}{a_1}=\frac{250}{333}=0.750

So, the next term will be

187\times 0.750\\\\=140.390

Hence, the common ratio is 0.750750....

and the next term is 140.390390.....

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What is the interquartile range of the following data set?
Anni [7]

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Convert 3\8 to a decimal and percent
Doss [256]

divide 8 into 3

    0.375

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8 0
4 years ago
Read 2 more answers
In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
3 years ago
Help please thank you
Ad libitum [116K]
In order for the triangle to be isosceles, we have to set two lengths of the triangle equal to each other. 

Let's take the lengths 5x-12 and x+20 and set them equal to each other. 

5x - 12 = x + 20 

Combine like terms by moving them over to their respective sides.

Subtract x from both sides of the equation. 

4x - 12 = 20 

Add 12 to both sides of the equation. 

4x = 32 

Divide both sides by 4. 

x = 8 

Check your answer by substituting. 

5x - 12 = x + 20

5(8) - 12 = 8 + 20

40 - 12 = 28 

28 = 28

Solution: x = 8 




5 0
3 years ago
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