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Gwar [14]
3 years ago
11

41. If n(G) = 20, n(H) = 30, n(G ⋂ H) = 5, find n(G ⋃ H) 42. If n(G) = 5, n(H) = 8, n(G ⋂ H) = 4, find n(G ⋃ H)

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0

Answer:

hope it will help

plz mark brainliest✌️✌️

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Answer: 12m^2+19m-18

Step-by-step explanation:

Given

Speed of boat v=3m-2\ \text{knots per hour}

\text{time t= }4m+9\ \text{hours}

\Rightarrow \text{Distance =speed}\times \text{time}

\Rightarrow \text{Distance d=}(3m-2)\cdot (4m+9)\\\Rightarrow d=12m^2+19m-18

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What are the answers to these and how do I do it
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1. D

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Step-by-step explanation:

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3 years ago
n HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you tha
Dominik [7]

Answer:

0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.39 ppm

Standard Deviation, σ = 4.25 ppm

Sample size = 11

We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.

Formula:  

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(printing speed of the sample is greater than 17.99 ppm.)  

P(x > 17.99)  

P( x > 17.99) = P( z > \displaystyle\frac{17.99-17.39}{\frac{4.25}{\sqrt{11}}}) = P(z > 0.468229)\\\\P( z > 0.468229) = 1 - P(z < 0.468229)

Calculating the value from the standard normal table we have,

1 - 0.679 = 0321= 32.1\%\\P( x > 17.99) = 32.1\%

Thus, 0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

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