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3 years ago

Which scale measures the amount of damage after an earthquake?

Physics

2 answers:

OLga [1]3 years ago

6 0

Mercalli Intensity Scale:

<em> is a seismic intensity scale used for measuring the intensity of an earthquake. ... It is distinct from the moment magnitude (Mw) usually reported for an earthquake, which is a measure of the energy released (sometimes misreported as the Richter magnitude, ML).</em>

IrinaVladis [17]3 years ago

4 0

Answer: The correct answer is "Mercalli intensity scale".

Explanation:

Mercalli Intensity Scale: It is an effect of an earthquake on the surface of the earth. It depicts the shaking severity. It measures the amount of damage after an earthquake or It measures the destruction.

Richter scale: It describes the magnitude of the earthquake by measuring the seismic wave. It is the energy released by the an earthquake.

Therefore, Mercalli intensity scale measures the amount of damage after an earthquake.

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A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider

shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

$d=v_x t$

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

$v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s$

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

$y(t) = h + v_y t - \frac{1}{2}gt^2$

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

$0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s$

So now we can find the magnitude of the initial velocity:

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s$

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Cause surface currents to move in circular paths.

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Explanation:

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3 years ago

A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration

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To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

$F_f = \mu N$

Where,

$\mu =$ Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

$m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\$

By condition of Balance the friction force must be equal to the total net force, that is to say

$F_{net} = F_f$

$m_{total}a = \mu m_hg$

$(m_h+m_c)a = \mu*m_h*g$

Re-arrange to find acceleration,

$a= \frac{\mu*m_h*g}{(m_h+m_c)}$

$a = \frac{0.894*242*9.8}{(242+224)}$

$a = 4.54 m/s^2$

Therefore the acceleration the horse can give is $4.54m/s^2$

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Answer:

the soild material is allowe to settle into a sludge layer the remaining waste water undergoes a secondart treatment that uses bacteria to break down organic matter

treat water is left to sit while particles settle out, with settle d particles being added to sluudge,

water is disinfeted

Explanation:

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