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Cloud [144]
3 years ago
10

Knowing that 1 inch is equal to 2.54 centimeters, convert 287 cm to inches.

Physics
2 answers:
umka2103 [35]3 years ago
6 0

Answer: 112.992

Explanation: If you divide 287 by 2.54, you will get 112.992125984. I just got rid of the five numbers after 992.

Misha Larkins [42]3 years ago
5 0

1 inch = 2.54 cm

?= 287 cm let, ? be (a)

cross multiply

2.54a= 1×287

a= 287/2.54

a= 112.992126

therefore 287 cm = 112.992126 inches.

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The motion of a particle is described by the position function s(t) = 2t - 15t +33t+17,t>0 , where is measured in seconds and
8090 [49]

The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at 0.

The total distance traveled in the first 10 seconds is 847 m.

<h3>When is a particle at rest?</h3>
  • A particle is at rest when the initial velocity of the particle is zero.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s

The velocity is positive at when the time of motion is as follows;

0.

The total distance traveled in the first 10 seconds is calculated as follows;

2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m

Learn more about motion of particles here: brainly.com/question/11066673

4 0
2 years ago
What is the central core of a atom
MariettaO [177]

Answer:

nucleus is the center of atom

7 0
3 years ago
I dont know how to do any of this so someone please help (the way it was solved has to be present for each thing) i will give br
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2 years ago
Three points A, B, and C of unknown charges are at the corners of an equilateral triangle.
nasty-shy [4]
Answer: option d. 

Q_A= \frac{1}{2} Q_B=- \frac{1}{3} Q_C

Explanation:


1) The direction of the field lines inform about the sign of the charges.

The field lines <span>extend from the positive charges to the negative charges, so you can conclude that the charge C is positve and both charge A and charge B are negative:
</span><span>
</span><span>
</span><span>Charge C: positive
</span><span>
</span><span>Charge A: negative
</span><span>
</span><span>Charge B: netative
</span>

2) The density of the lines (number of lines in a region) inform about the magnitude of the electric field.

Since the charges are at the same distance, the magnitude of the electric field informs directly about the magnitude of the force and that about the magnitude of the charges.

Since, there are the double of lines between C and B than between C and A, the magnitude of charge B is the double than the magnitud of charge A.

From the five options given (a throug e) the only that is consistent with that charges A and B have the same sign, that charge C has different sign, and that charge B is the double of charge A is:

Q_A= \frac{1}{2} Q_B=- \frac{1}{3} Q_C
3 0
3 years ago
Si un auto se mueve en rapidez constante de 25,0m/s a lo largo de 2500 m en línea recta, ¿cuál es la magnitud de la fuerza resul
Nataly_w [17]

Answer:

F= 0

Explanation:

This exercise we use Newton's second law,

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in this case as the speed is constant the acceleration is zero therefore the force is zero.

Change we can solve it using Newton's first law, which states that every vehicle remains still or with constant speed if there is no extensive outside acting on it

We see that with any of the two forms the sum of the applied forces is zero

                     ∑ F = 0

3 0
3 years ago
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