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Otrada [13]
4 years ago
13

What’s the kinetic energy of the roller coaster at the top and bottom of the hill? Use . A kiddie roller coaster car has a mass

100 kilograms. At the top of a hill, it’s moving at a speed of 3 meters/second. After reaching the bottom of the hill, its speed doubles. The car’s kinetic energy at the bottom is its kinetic energy at the top. The car has joules of kinetic energy at the bottom of the hill.
Physics
2 answers:
serious [3.7K]4 years ago
0 0
K.E1=1/2×100×3²
=50×9
=450J
K.E2=1/2×100×36
=50×36
=1800J
Ymorist [56]4 years ago
0 0

double, 1800

if the speed doubles ,then so does the kinetic energy and 3 would turn into 6

Now we use KE=1/2mv^2

1/2 x 100= 50 x 6^2 = 1800


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Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

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solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

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solve it we get

final speed V = 16.60 m/s

and

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Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

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6 0
3 years ago
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Marta_Voda [28]

Answer:

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a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

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