Answer:
What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
Explanation:
What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
Answer:
A. Expanding personal knowledge by reading articles from scientific
journals
B. Analyzing the different parts of a physical phenomenon to see
how they fit together
C. Predicting the impact that answering an important scientific
question would have on people
D. Developing a question that can be answered through testing or
observation
E. Developing logical arguments for providing incentives for
scientific research
Answer:
Materials can be classified based on the amount of light they transmit. Materials, which allow complete transmission of light, are called transparent. Any object can be seen through a transparent material. One example of transparent material is pure glass.
Explanation:
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Answer:
is the initial velocity of tossing the apple.
the apple should be tossed after 
Explanation:
Given:
- velocity of arrow in projectile,
- angle of projectile from the horizontal,
- distance of the point of tossing up of an apple,
<u>Now the horizontal component of velocity:</u>
<u>The vertical component of the velocity:</u>
<u>Time taken by the projectile to travel the distance of 30 m:</u>
<u>Vertical position of the projectile at this time:</u>
<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>
is the initial velocity of tossing the apple.
<u>Time taken to reach this height:</u>
<u>We observe that </u>
<u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>
