A 0.45-m metal rod moves 0.11 m in a direction that is perpendicular to a 0.80-T magnetic field in an elapsed time of 0.036 s. A

Question

Tomtit [17]

3 years ago

5

A 0.45-m metal rod moves 0.11 m in a direction that is perpendicular to a 0.80-T magnetic field in an elapsed time of 0.036 s. A

ssuming that the acceleration of the rod is zero m/s2, determine the emf that exists between the ends of the rod.

Physics

2 answers:

madam [21] · Answer 1 · 2021-12-16T16:57:07+03:00

Answer:

(B) This cannot be determined without knowing the orientation of the rod relative to the magnetic field.

Because, Since acceleration of the rod is Zero. So, net force acting on the rod will be zero. But, its not specified that whether the rod is moving along varying magnetic field direction or a constant magnetic field direction.

Gwar [14] · Answer 2 · 2021-12-16T15:53:05+03:00

Gwar [14]3 years ago

3 0

Answer:

1.1 V

Explanation:

L = 0.45 m

d = 0.11 m

B = 0.80 T

t = 0.036 s

Let e be the emf.

e = B v L

e = 0.80 x 0.11 x 0.45 / 0.036 = 1.1 V