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jenyasd209 [6]
3 years ago
13

What enzyme is coded for in the chromosome of bacteria?

Chemistry
2 answers:
Anika [276]3 years ago
5 0

Da answer is A

I promise its not cap

Mariulka [41]3 years ago
3 0
The correct answer would be, "<span>D. beta-galactosidase".
As all the others are made in different organisms.

Hoped I helped.</span>
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If 2.68 g of benzaldehyde are involved with the mixed aldol condensation reaction, how many moles of benzaldehyde are present? R
Zielflug [23.3K]

Answer:

The number of moles of benzaldehyde = 0.0253 moles

Explanation:

The molecular formula of benzaldehyde is C₇H₆O

Its molecular mass is calculated from the atomic masses of the constituent atoms.

C = 12.0 g: H = 1.0 g; O = 16.0 g

Molecular mass = ( 12 * 7) + (1 * 6) + (16 * 1) = 106.0 g/mol

Number of moles of  substance = mass of substance/ molar mass of the substance

mass of benzaldehyde = 2.68; molar mass = 106.0 g/mol

Number of moles of benzaldehyde = 2.68 g/ 106 g/mol = 0.0253 moles

Therefore, the number of moles of benzaldehyde = 0.0253 moles

8 0
3 years ago
Why were scientists unsure about the last common ancestor between apes and humans?
nadezda [96]

Answer:

Scientists were unsure about the last common ancestor between apes and humans because fossils are so scarce, researchers do not know what the last common ancestors of living apes and humans looked like or where they originated.

Explanation:

7 0
3 years ago
Calculate the volume of a 2.0 molar aqueous solution made from 14 miles of K2S
Vilka [71]

Answer:

volume is 7.0 liters

Explanation:

We are given;

  • Molarity of the aqueous solution as 2.0 M
  • Moles of the solute, K₂S as 14 moles

We are required to determine the volume of the solution;

We need to know that;

Molarity = Moles ÷ volume

Therefore;

Volume = Moles ÷ Molarity

Thus;

Volume of the solution = 14 moles ÷ 2.0 M

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Hence, the volume of the molar solution is 7.0 L

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Answer:

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3 years ago
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A transfer of heat within a liquid or gas that involves warm particles moving in currents is?
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3 years ago
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