The answer is 3.63. seconds.
Second order reaction is the reaction in which the rate of reaction depends on either the concentration of two reactant species or on the two times the concentration of single reactant species.
What is the integrated rate law for the second-order reaction?
- The integrated rate law that relates the concentration, time and rate constant for the second-order reaction is:
![\frac{1}{[A]} =\frac{1}{[A]_{0} } +kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D%20%2Bkt)
Where
![\[\begin{array}{l}{\rm{[A] - concentration\ of\ reactant\ A\ at\ time\ t}}\\{{\rm{[A]}}_0}{\rm{ - initial\ concentration\ of\ reactant\ A}}\\{\rm{t - time}}\\{\rm{k - rate\ constant}}\end{array}\]](https://tex.z-dn.net/?f=%5C%5B%5Cbegin%7Barray%7D%7Bl%7D%7B%5Crm%7B%5BA%5D%20%20-%20%20concentration%5C%20of%5C%20reactant%5C%20A%5C%20at%5C%20time%5C%20t%7D%7D%5C%5C%7B%7B%5Crm%7B%5BA%5D%7D%7D_0%7D%7B%5Crm%7B%20-%20%20initial%5C%20concentration%5C%20of%5C%20reactant%5C%20A%7D%7D%5C%5C%7B%5Crm%7Bt%20-%20time%7D%7D%5C%5C%7B%5Crm%7Bk%20%20-%20%20rate%5C%20constant%7D%7D%5Cend%7Barray%7D%5C%5D)
- Now, in the given question,
k = 
![[NO_{2} ]= 0.62\ M](https://tex.z-dn.net/?f=%5BNO_%7B2%7D%20%5D%3D%200.62%5C%20M)
![[NO_{2} ]_{0} = 0.28\ M](https://tex.z-dn.net/?f=%5BNO_%7B2%7D%20%5D_%7B0%7D%20%3D%200.28%5C%20M)
- Thus, using the rate law, the time is calculated as-
Therefore,
- Hence, the it would take 3.63 seconds for the concentration of
to decrease from 0.62 M to 0.28 M if the reaction is second order.
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With that informatio you can:
1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.
I will do all four, for you:
1) Chemical equation:
mercury(I) nitrate potassium bromide mercury(I) bromide potassium nitrate
<span>Hg2(NO3)2 + KBr → Hg2Br2 + KNO<span>3
2) Balanced chemical equation
</span></span>
<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3
3) Molar ratios or proportions:
1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3
4) Prediction of precipitation.
You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.
</span></span>
Answer:
Engineers changed the world, such as building houses, bridges, and cars.
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Answer:
λ=2167.6 nm
The wavelength of light emitted is 2167.6 nm.
Explanation:
We recall that Eₙ=
since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE
ΔE=E₄-E₇
ΔE=
ΔE=-9.1760*10^-20 J
Now:
|ΔE|=Energy of photon=h*v=h*c/λ
λ=h*c/|ΔE|
λ=
λ=2.1676*10^-6 m
λ=2167.6*10^-9 m
λ=2167.6 nm
The wavelength of light emitted is 2167.6 nm.
