Answer:
(1). The vapor pressure is 91 mmHg at 20°C.
(2). No, benzene will not boil at sea level.
Explanation:
Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.
The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.
Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.
The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).
71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.
I don’t know what to do with the answer I don’t know how you feel sorry I didn’t
The answer is weak intermolecular attractions volume and shape of container. The molecules of gases have high kinetic energy compared to those of liquids and solids hence they are farther apart from one another. This results to weak intermolecular forces. Gases also expand to fit the container hence have no definite shape or volume.
Answer:
The answer is
<h2>12,574,750.83 moles</h2>
Explanation:
In order to find the moles of CO2 we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
N = 7.57 × 10^30 molecules of CO2
We have
We have the final answer as
<h3>12,574,750.83 moles</h3>
Hope this helps you
Answer:
The new volume is 808L.
Explanation:
First, you need to set up your proportion, using Charles's law.
V1 V2
<u> </u> = <u> </u>
T1 T2
Then, substitute for the ones you already know.
625 L V2
<u> </u> = <u> </u>
273 K 353 K
Then, you need to cross multiply.
625 x 353 = 273 x V2
Then, solve for V2.
220625 = 273 x V2
220625 ÷ 273 = V2
808 = V2
The final volume is 808L.
