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yulyashka [42]
3 years ago
7

Ammonia is an important ingredient in many fertilizers. The main process by which ammonia is made is the Haber process. In this

process, nitrogen gas and hydrogen gas are reacted to form ammonia at high temperatures. This sentence most likely explains why this reaction is carried out at high temperature.
A.) Ammonia is unstable at room temperature.
B.) High temperatures increase the activation energy of the reaction.
C.) High temperatures make the gas molecules move more quickly.
D.) The reaction becomes exothermic at high temperatures.
Chemistry
2 answers:
Basile [38]3 years ago
8 0
"High temperatures make the gas molecules move more quickly" is the one sentence among all the choices given in the question that most likely explains why this reaction is carried out at high temperature. The correct option among all the options that are given in the question is the third option or option "C".
Doss [256]3 years ago
5 0

Answer:

3rd one / C

Explanation:

The correct answer is that "The highest temperatures make the gas molecules move more quickly."

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Hitman42 [59]

Exothermic reactions is where  energy is released. Exothermic reactions are reactions that release energy into the environment in the form of heat. Exothermic reactions feel warm or hot or may even be explosive.

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3 years ago
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

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3 years ago
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Leno4ka [110]

Answer:

It has been approximately 6 hours after death.

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