Answer:
2.15
Explanation:
For this question, we have to remember the <u>pH formula</u>:
![pH~=~-Log[H_3O^+]](https://tex.z-dn.net/?f=pH~%3D~-Log%5BH_3O%5E%2B%5D)
By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (
). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

With this value, now we can calculate the pH value:
![pH~=~-Log[0.00693~M]~=~2.15](https://tex.z-dn.net/?f=pH~%3D~-Log%5B0.00693~M%5D~%3D~2.15)
<u>The pH would be 2.15</u>
I hope it helps!
Answer:
C. 3.40 ppm, singlet
Explanation:
Given the information from the question .we have to select the best representation for represents the predicted approximate chemical shift and coupling for hydrogen(s). In this case, there is no neighboring hydrogen .Thus there won’t be any split .the best option answer is C. 3.40 ppm, singlet . Therefore the correct answer or option is C. 3.40 ppm, singlet.
Answer:
A combination reaction
Explanation:
The chemical reaction between ammonia and hydrochloric acid as shown below:
NH₃ + HCl → NH₄Cl
is a combination reaction.
In a combination reaction, two compounds combines together to give one compound.
A combination reaction is also known as a synthesis reaction.
A single product forms from tow or more reactants.
The driving force for such reaction is the large and negative heat of formation of the product.
Answer:
0.5077 moles
Explanation:
Data Given:
Moles = n = <u>???</u>
Temperature = T = 300 K
Pressure = P = 380 mmHg = 0.50 atm
Volume = V = 25 L
Formula Used:
Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,
P V = n R T
where; R = Universal Gas Constant = 0.082057 atm.L.mol⁻¹.K⁻¹
Solving Equation for n,
n = P V / RT
Putting Values,
n = (0.50 atm × 25 L) / (0.082057 atm.L.mol⁻¹.K⁻¹ × 300 K)
n = 0.5077 moles