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tigry1 [53]
3 years ago
12

A set of equations is given below: Equation A: q = 4r + 1 Equation B: q = 3r + 5 Which of the following is a step that can be us

ed to find the solution to the set of equations? 4r + 1 = 3r 4r = 3r + 5 4r + 1 = 3r + 5 4r + 5 = 3r + 1
Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0
Hi

The correct option is 4r + 1 = 3r + 5
-------------------------------------------------------

Because you need to solve q = 4r + 1 for q . After that, you'll have to substitute 4r + 1 for q in q = 3r + 5


Good luck! 
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8=p/8 one steo equations
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yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

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3 years ago
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Vera_Pavlovna [14]

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Step-by-step explanation:

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zhuklara [117]

Answer:

The answer should be B

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4 0
3 years ago
Read 2 more answers
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