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tigry1 [53]
3 years ago
12

A set of equations is given below: Equation A: q = 4r + 1 Equation B: q = 3r + 5 Which of the following is a step that can be us

ed to find the solution to the set of equations? 4r + 1 = 3r 4r = 3r + 5 4r + 1 = 3r + 5 4r + 5 = 3r + 1
Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0
Hi

The correct option is 4r + 1 = 3r + 5
-------------------------------------------------------

Because you need to solve q = 4r + 1 for q . After that, you'll have to substitute 4r + 1 for q in q = 3r + 5


Good luck! 
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The distance traveled by a car moving at 30 miles per hour for t hours
Inga [223]
D = t*s
distance = time * speed
d = t*30
8 0
3 years ago
Need Help ....!!!
postnew [5]

\\ \sf\longmapsto \dfrac{(0.0225)^{\frac{-3}{2}}\times (0.0001)^{\frac{3}{4}}}{(0.0125)^{\frac{1}{3}}}

\\ \sf\longmapsto \dfrac{((0.15)^2)^{\frac{-3}{2}}\times ((0.1)^4)^{\frac{3}{4}}}{(0.5)^3)^{\frac{1}{3}}}

\\ \sf\longmapsto \dfrac{(0.15)^{2\times \dfrac{-3}{2}}\times (0.1)^{4\times \dfrac{3}{4}}}{(0.5)^{3\times \dfrac{1}{3}}}

\\ \sf\longmapsto \dfrac{(0.15)^{-3}(0.1)^3}{(0.5)^1}

\\ \sf\longmapsto \dfrac{\dfrac{1}{(0.15)^3}\times 0.001}{0.5}

\\ \sf\longmapsto \dfrac{\dfrac{1}{0.003375}(0.001)}{0.5}

\\ \sf\longmapsto\dfrac{ \dfrac{1000000}{3375}\times \dfrac{1}{1000}}{0.5}

\\ \sf\longmapsto \dfrac{\dfrac{1000}{3375}}{0.5}

\\ \sf\longmapsto \dfrac{1000}{3375}\times \dfrac{10}{5}

\\ \sf\longmapsto \dfrac{2000}{3375}

\\ \sf\longmapsto 0.592

4 0
2 years ago
Determine the slope of the line.
Akimi4 [234]

Answer:

2

Step-by-step explanation:

→ Find 2 points from the line

( 0 , 6 ) and ( - 3 , 0 )

→ Find the change in y coordinates

0 - 6 = -6

→ Find the change in x coordinates

-3 - 0 = -3

→ Divide the 2 results

-6 ÷ -3 = 2

7 0
2 years ago
There is a triangle with measures of 5, 12, 14. Is this a right triangle? Why or why not?
AlladinOne [14]

Answer:

no,it isnt,

Step-by-step explanation:

pythagoras property of right angle:

height sq + base square = hypotenuse sq

5*2+12*2=14*2

25+144=196 which is wrong

5 0
2 years ago
PLEASE HELP ME!!
tatiyna
For
y=ax²+bx+c
the x value of the axis of symmetry is -b/(2a)

so test them

A., -b/(2a)=-(-8)/(2*-2)=8/-4=-2, yep
B. -b/(2a)=-2/(2*1/2)=-2/1=-2, yep
C. -b/(2a)=-(-16)/(2*4)=16/8=2, nope, need -2
D. -b/(2a)=-12/(2*3)=-12/6=-2, yep

answer is C
3 0
3 years ago
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