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Gnesinka [82]
3 years ago
6

You are playing a dice game called Noluz against one other person. Each time you play, both players pay a quarter. You win the m

oney if a 1 or 4 shows face up on the die. The other player wins if a 2 or 5 comes up, and the piggy bank gets the money if a 3 or 6 comes up. This money will then be donated to a charity that you pick. What is the expected value per turn for playing Noluz?
Mathematics
2 answers:
Vlad [161]3 years ago
6 0
Assuming a fair die, 
probability of winning 0.25 = (2/6) = 1/3
probability of losing 0.25 = (4/6) = 2/3

Expected win
= sum (proba.*winning)
=0.25*(1/3) + (-0.25)(2/3)
=-0.25/3
= - (1/12) dollars  (negative sign means expecting to lose)
taurus [48]3 years ago
3 0

Answer:

$-0.17

Step-by-step explanation:

Expected value: You're paying $0.25, which means you lose $0.25 initially, or you gain $-0.25.

Then you have a chance to get that $0.25 back, but only if you can land that 1/3 chance of winning.

ExpectedGain = Probability * AmountToGain

EG = 1/3 * 0.25 = 1/12

Now that we know this is the expected gain, lets not forget the amount we spend in the first place:

-0.25 + 0.083 = -0.17 approx.

Hope this helps, please let me know if I made a mistake because I am just now studying this.

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Answer:

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Step-by-step explanation:

First, you do 65 ÷ 3 = 21.7 if rounding to the tenths, 21.67 if to the hundredths, and so on. Then you do 21.67 - 12 = 9.67. But since it is cards, I would say about 9 left.

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