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mixas84 [53]
3 years ago
11

PLEASE HELP!! ONLY RIGHT ANSWERS PLEASE!!!

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

1

Step-by-step explanation:

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Consider the numbers 4/15 and 3/10 (a) Compare the numbers. (B) find a fraction between the two given numbers
valentinak56 [21]
As a decimal 4/15 = 0.2666667
As a decimal 3/10 = 0.3 [talk about close]
3/10 is bigger.

You could take an average to find something between 4/15 and 3/10
1/2(4/15 + 2/10)
1/2(8/30 + 6/30)
1/2(14/30)
1/2(7/15)
7/30 is between the two given numbers..
5 0
3 years ago
Micah is watching a TV program that is 2 hours long during the program there are six commercials that are each 90 sec. How many
Sergeu [11.5K]

Answer:

111 minutes

Step-by-step explanation:

step 1

Find out how long are the six commercial

Multiply the number of commercials by 90 seconds

so

90(6)=540\ sec

Convert to minutes

Remember that

1\ min=60\ sec

540\ sec=540/60=9\ min

step 2

Subtract the duration of six commercials from the duration of the program

Remember that

1\ h=60\ min

so

2\ h=2(60)=120\ min

therefore

120-9=111\ min

4 0
3 years ago
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
3 years ago
Which of the following fractions will convert to terminating decimals? A.5/6
dexar [7]

Answer:

answer E

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve for x in the equation X2-8x+41 = 0 -
djverab [1.8K]

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D  

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation  ax² + b x + c = 0

The value of x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

∴ For equation x² - 8 x + 41 = 0

Or,                x = \frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}

Or,                x = \frac{8\pm \sqrt{-100}}{2}

Or,                x = \frac{8\pm 10i}{2}

∴                  x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D     Answer

7 0
4 years ago
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